Sean O'Connor's Games

just a technicality, I think the threat warning goes off even when a guided missile would aim at a different target that is, say, somewhere between you and the enemy, so long as you are within a certain range of that enemy. you can try to predict how the enemy missiles will move and take advantage o...

using more wingmen is fun, but i find that cheaper ships really can't stand up to the stronger enemies. also, i usually use a radar guy but the use of radars inherently makes it weaker and more susceptible to death. i also usually don't give drachans to my fighter wingmen, they just don't cut it in ...

true that, especially when you get very outnumbered in the more difficult missions. you'll have to run around smashing as many enemies as you can without wasting time chasing crippled enemies.

whoa, your explanation belies how intuitive the process actually is, though i'm glad he got it
and yeah, this isn't the kind of place where people with too much time on their hands spend it by flaming others. we are the true harcore gamers!!!1one

i think that's a great idea, though i would believe there would be difficulties with the number of credits each person has and choosing the mission, unless you always do each mission from the start with 350 credits or something

well, it could just as well be a glitch

care to share your newfound wisdom? :3

yeah, that's pretty much what i did, except it's not the pythagorean theorem but basic trigonometry (or alternatively law of sines), and i was half thinking in radians and half in degrees, as if you use radians you don't have to calculate circumference, divide by 360 and multiply by that angle, just...

o crap, the stuff i posted earlier was a bit wrong. the 90s in the trig functions are 90 degrees. but yeah, good luck on that.

well, don't you need B?ziers for the arc approximations? the distance i gave is the exact total distance the ship would travel in a circular arc, and the total rotation is 2θ. θ is the angle between the line the ship travels in if there is no turn and the line between mouse and ship. for example, if...

in case you couldn't find this from the program, i have found that in a perfectly circular arc the distance traveled will be r * 2θ * sin(90 - θ) / sin(2θ) or 2θ * (r/2) / cos(90 - θ) where r is the distance between mouse and ship and θ is in radians. these values are radius of curvature times angle...

wow, so i was completely off (i just checked using a ruler on my screen too lol). however, i still believe that the turn is double the angle between the "no turn" line and the line between mouse and ship. just in case, i will mention that i'm pretty sure acceleration works instantaneously at the sta...

from what i can see, the acceleration is based on distance from the center of the ship , i.e. distance formula with the square root of the sum of the squares. the ship will have some set velocity, including the "speed" or the distance the ship will travel (which i suspect is measured in pixels), and...

heh, so were those drones

well...i'd say 3 launchers is a must for a good ship. and what do you mean by "best" designs?